Equilibre D 39un Solide Soumis A 3 Forces Exercice Corrige Pdf Exclusive !!exclusive!! Jun 2026

From geometry: Triangle ABC: AB = 2 m, midpoint M, AM = 1 m. In triangle MBC: MB = 1 m. Vertical line from M, string from B at 30° → C is above rod. Coordinates: A(0,0), B(2,0), M(1,0). String equation from B: y = tan(30°)(x – 2) = 0.577(x – 2). Vertical line at x=1: y = 0.577(1 – 2) = -0.577? Negative means intersection below – impossible. Wait – error: String is from B to wall horizontal? If angle with horizontal is 30°, from B to wall left-up, slope positive? No, if wall is vertical left of A, string goes from B(2,0) to a point on wall (0, y_w). Slope = (y_w – 0)/(0 – 2) = -y_w/2. Given angle 30° with horizontal, slope = tan(30°) = 0.577 if measured from horizontal, but direction left-up means slope positive? Actually from B to wall, Δx = -2, Δy positive, so slope = Δy/Δx negative? No – slope magnitude = 0.577 but sign negative because Δx negative. Let’s do properly:

0+Rn−T⋅sin(α)=0⟹Rn=T⋅sin(α)0 plus cap R sub n minus cap T center dot sine open paren alpha close paren equals 0 ⟹ cap R sub n equals cap T center dot sine open paren alpha close paren From geometry: Triangle ABC: AB = 2 m, midpoint M, AM = 1 m

R=(Pcos(α))⋅sin(α)=P⋅tan(α)cap R equals open paren the fraction with numerator cap P and denominator cosine open paren alpha close paren end-fraction close paren center dot sine open paren alpha close paren equals cap P center dot tangent open paren alpha close paren Application numérique : Coordinates: A(0,0), B(2,0), M(1,0)

The three force vectors, placed head-to-tail, form a closed triangle. Negative means intersection below – impossible

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